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0=x^2+2x-70
We move all terms to the left:
0-(x^2+2x-70)=0
We add all the numbers together, and all the variables
-(x^2+2x-70)=0
We get rid of parentheses
-x^2-2x+70=0
We add all the numbers together, and all the variables
-1x^2-2x+70=0
a = -1; b = -2; c = +70;
Δ = b2-4ac
Δ = -22-4·(-1)·70
Δ = 284
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{284}=\sqrt{4*71}=\sqrt{4}*\sqrt{71}=2\sqrt{71}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{71}}{2*-1}=\frac{2-2\sqrt{71}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{71}}{2*-1}=\frac{2+2\sqrt{71}}{-2} $
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